pi/rtx5090/qwen3.8-flash-next-iq4_nl-ggml

Trivial character count; I counted by hand and re-checked with a quick string count to avoid an off-by-one on repeated letters.

Simple magnitude comparison — 5.9 versus 5.28 is a trap for treating the longer mantissa as bigger, but 0.90 beats 0.28. No difficulty.

Routine once I suppressed normal operator precedence and folded strictly left to right: 25-18=7, *5=35, +14=49, /7=7. The only risk is reflexively applying precedence, which would give a different number.

Mechanical: 14 km = 14000 m, then the same number restated as kg gives 14,000,000 g. The only wrinkle is ignoring that the units changed meaning, which the prompt explicitly asks for.

Format-following rather than math: keys in the requested order, answer as a string, checksum as a JSON number (8+9+8+8=33). Easy, though I had to make sure I did not quote the number.

Trivial addition, 12 + 2 = 14. No ambiguity or effort at all.

Plain three-digit addition: 923 + 461 = 1384. Checked the carry into the hundreds place; nothing tricky.

Straightforward: (6 * 8) - 81 - 58 = 48 - 139 = -91. Verified the sign handling on the negative terms with a quick check.

I expanded along the first row by hand, got -878, then re-derived it by a second cofactor expansion (down column 1) and by the permutation definition to make sure I had not flipped a cofactor sign. All three agreed, so I am confident.

The row-4 group-1 line is small at full-image scale, so I cropped and upscaled it 4x before reading; it clearly reads VK7PS. Cropping was the key step — at native scale the P and S were ambiguous.

Row 5 group 3 is only about 10px tall in the full image, so I located the text bands programmatically, cropped that cell and upscaled it. Readable after upscaling, though the 6 and M were slightly soft from antialiasing.

Row 6 group 1 was ~7px tall; after cropping and 20x+ upscaling I read U-J-J-Q-S. The first glyph is the only one I would call marginally ambiguous (U vs V) but it has a rounded bottom, so U.

Smallest row yet (~6px). Upscaling made it legible as K2VA3; the second character could theoretically be Z but it has the curved top of a 2, and no other glyph was uncertain.

Routine. I segmented by exact colour (violet #7C3AED) and labelled connected components: four purple triangles, plus green squares, blue/orange circles and a teal diamond as distractors. Visual check agreed with the pixel count.

Colour+shape segmentation: 19 green components, of which 15 had the diamond width profile (narrow-wide-narrow), 2 were triangles, 1 circle, 1 square. Counted them by eye row by row as a cross-check and got the same 15.

Too many shapes to count reliably by eye, so I labelled connected components of the exact orange RGB value and classified each by bbox fill ratio (0.77 = circle, 0.52 = triangle, 0.99 = square): 37 orange circles, 8 orange triangles, 5 orange squares. I am fairly confident in the pixel count but did not manually re-verify all 37.

Easy once I stopped eyeballing it: I found the single red component (bbox fill 0.79, so a circle) at pixel (1027-1147, 87-207) and derived the 5x5 grid from the gridline pixel columns, which puts it in row 1, column 5.

The chart has two arrows touching the teal triangle (one in, one out), so just looking at it made me double-check direction. I traced every dark line as a connected component, found its two endpoints by PCA and located the arrowhead by local pixel density: the outbound arrow from the teal triangle ends on the blue circle at row 5, col 3.